Question
Anil, Bheem and Tina can complete a work separately in
12, 18 and 24 days respectively. They started together but Tina left after 4 days of start and Anil left 3 days before the completion of the work then,In how many days will the work will complete?Solution
ATQ we can say that, Let the total work be(L.C.M of 12,18 and 24) = 72 units. Anilâs one day work = 72/12 = 6 units Bheemâs one day work = 72/18 = 4 units Tinkuâs one day work = 72/24 = 3 units (Anil + Bheem + Tinku)âs 4 days work = ((6 x 4) + (4 x 4)+ (3 x 4)) = = 24 + 16 + 12 = 52 units Anilâs 3 days work = 18 units Number of days for which (Anil + Bheem) worked together = 72â52+(18/10) = 3.8 days Hence, required number of days = 7.8 days
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