Question
108 unit of work can be completed by P alone in 18 days.
P started working alone and joined by Q after 9 days such that they completed the remaining work in 3 days. Find the number of days taken by Q to complete the whole work alone.Solution
Let the efficiency of Q = x units/day Efficiency of P = (108/18) = 6 units/day According to question: 6 × 9 + (6 + x) × 3 = 108 Or, 54 + 18 + 3x = 108 Or, 3x = 108 – 72 Or, 3x = 36 Or, x = 12 Number of days taken by Q to complete the work alone = (108/12) = 9 days
I: x2Â + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I. x² - 33x + 270 = 0
II. y² - 41y + 414 = 0
I. 5x² + 17x + 6 = 0                     Â
II. 2y² + 11y + 12 = 0
...I. 195x² - 46x - 21 = 0
II. 209y² + 7y - 12 = 0
I. 3x2 - 16x - 12 = 0
II. 2y2 + 11y + 9 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. 27(p + 2) = 2p(24 – p)
II. 2q2 – 25q + 78 = 0
I. 5x² -14x + 8 = 0 Â
II. 2y² + 17y + 36 = 0  Â
What is the nature of the roots of the quadratic equation x² – 5x + 7 = 0 ?Â
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