Question
108 unit of work can be completed by P alone in 18 days.
P started working alone and joined by Q after 9 days such that they completed the remaining work in 3 days. Find the number of days taken by Q to complete the whole work alone.Solution
Let the efficiency of Q = x units/day Efficiency of P = (108/18) = 6 units/day According to question: 6 × 9 + (6 + x) × 3 = 108 Or, 54 + 18 + 3x = 108 Or, 3x = 108 – 72 Or, 3x = 36 Or, x = 12 Number of days taken by Q to complete the work alone = (108/12) = 9 days
6000 3002 1503 ? 378.75 191.375 97.6875
...1, 27, ?, 343, 729, 1331
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
51 53 109 332 ? 6686
...9 4.5 4.5 9 36 ?
5 16 ? 66 119 200
...1 1 8 4 27 9 ?
...What will be the next number in the series?
2, 7, 23, 70, ?
There are three series given below which are following with the same pattern.
Series I: 1, 12, 38, 193, 1355
Series II: 6, B, C, D, E
...Direction: Which of the following will replace ‘?’ in the given question?
5, 18, ‘?’, 126, 296, 586, 1044
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