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Let the total work be (LCM of 15 and 20) = 60 units Efficiency of Anil = 60/20 = 3 units/day Remaining work = 60 x 0.4 = 24 units Time taken by Anil to complete the remaining work = 24/3 = 8 days
185.92 ÷ 5.98 - (4.002)2 + 114.03 of 5.03 ÷ 18.99 of 6.04 = 5.01 of 2.99 + ? ÷ 12.02
1587.9 + 9650.98 + 10612.8 =?3 - 2536.67
64.64% of 419.89 + 116.61 = ? x 12.89
68.98 × 41.03 – (12.33)² + 15.78% of 8398.87 = ? – 40.22
?% of (136.31 ÷ 16.97 × 75.011) = 179.98
9.992 + (5.01 × 4.98) + ? = 225.03
(9.013 – 15.04) = ? + 7.98% of 5199.98
(√1157 + 10.15% of 159.89) × 4.85 + 150.25 = ? × 19.67
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?