Question
X, Y, and Z alone can complete a language translation in
60, 90, and 36 days respectively. They started working together, but after 5 days, Z left the job, and 20 days before completion, X also left the job. In how many days is the translation completed?Solution
ATQ, Let the total work = 180 units (LCM of 60, 90, and 36) Amount of work done by X alone in one day = 180/60 = 3 units Amount of work done by Y alone in one day = 180/90 = 2 units Amount of work done by Z alone in one day = 180/36 = 5 units Amount of work done by X, Y, and Z together in 5 days = 5 × (3 + 2 + 5) = 50 units Amount of work done by Y alone in 20 days = 20 × 2 = 40 units Remaining work = 180 – 50 – 40 = 90 units Time taken by X and Y together to complete 90 units work = 90/(3 + 2) = 18 days So the total time taken to complete the translation = 5 + 20 + 18 = 43 days
(60/15) × 25 + 15 2 – 18% of 200 = ? 2
40% of 1820 + 80% of 630 = 90% of 1280 + ?
(750 / 15 × 15 + 152 + 20% of 125) = ?3
((67)32 × (67)-18 / ? = (67)⁸
72% of 486 – 64% of 261 = ?
The value of {5 − 5 ÷ (10 − 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:
(25)² × 4 ÷ 5 + (3)³ + 48=? + 425
In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantit...
√ (573 – 819 + 775) = ? ÷ 3
- What will come in the place of question mark (?) in the given expression?
(198/13) X (52/11) - ? ÷ 5 = 13 + 68 ÷ 4