Question
A man, a woman and a boy can do a work in 3, 2, 6 days
respectively. How many children were required with 1 man and 1 woman to complete the same work in 1/2 day?Solution
Work done by a man in (1 )/(2 ) days = (1 )/(6 ) part Work done by a woman in (1 )/(2 ) days = (1 )/(4 ) part Work done by a boy in (1 )/(2 ) days = (1 )/(12 ) part Let one man and one woman together can do a piece of work in (1 )/(2 ) days = No. of x children required According to the question, (1 )/(6 ) + (1 )/(4 ) + (x )/(12 ) = 1 (2 + 3 + x )/(12 ) = 1 5 + x = 12 x = 12 – 5 = 7 Hence, 7 boys will be required.
Statements: L < E; M = O; E >K ≥ M
Conclusions:
I. L < M
II. K = O
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