Question
‘M’ is 60% more efficient than ‘N’. ‘N’
started the work alone and worked for 16 days and after that ‘N’ is replaced by ‘M’. If the total work is completed in 26 days, find the time taken by ‘M’ to finish the same work alone?Solution
Let the efficiency of ‘N’ = ‘5x’ units/day Efficiency of ‘M’ = ‘8x’ units/day Time taken by ‘M’ to complete the remaining work = 26 – 16 = 10 days Total work = 16 × 5x + 10 × 8x = 160x units Desired time = 160x/8x = 20 days
(√3364+ √484) – √2916÷ √1296 × √36 ÷ √64 = ?
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