Question
A can complete a work in 30 days. B takes 6 days less
than A to complete the same work. In how many days can both of them together complete 60% of the work together?Solution
Time taken by B to complete the work = 30 – 6 = 24 days Let the total work = 120 units Efficiency of A = 120/30 = 4 units/day Efficiency of B = 120/24 = 5 units/day Required time taken = 0.60 x 120/(4+5) = 8 days
More Time and work Questions
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
