Question
A, B, and C together can do a work alone in 14 days, 56
days, and 70 days respectively. A alone starts the work and work for 3 days and leaves the work, then B alone does the work for 8 days and leaves the work. If remaining work is done by C alone then for how many days has C worked?Solution
Total work = LCM of 14, 56 and 70 = 280 units Unit per day of A = 280/14 = 20 Unit per day of B = 280/56 = 5 Unit per day of C = 280/70 = 4 Units of work done by A in 3 days = 20 × 3 = 60 units Units of work done by B in 8 days = 8 × 5 = 40 units Remaining work = 280 – (60 + 40) = 180 units So, C has worked for 180/4 = 45 days
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