Question
A and B together can do a work in 6 days. If A can alone
do the same work in 9 days, then in how many days B alone will do the same work?Solution
Total work = Number of days × 1 day’s work (efficiency) Total work = LCM (6, 9) = 18 unit 1 day’s work of (A+B) = 18/6 = 3 unit 1 day’s work of A = 18/9 = 2 unit 1 day’s work of B = 3 - 2 = 1 unit Now, Time taken by B to completed the work = 18/1 = 18 days
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