Question
A can do a work in 9 days and B in 12 days. If they work
on it together for 3 days then in how many days the remaining work will be completed by B?Solution
Total work = Number of days × 1 day’s work (efficiency) Total work = LCM (9, 12) = 36 unit 1 day’s work of A = 36/9 = 4 unit 1 day’s work of B = 36/12 = 3 unit 1 day’s work of (A + B) = 4 + 3 = 7 unit Now, 3 day’s work of (A + B) together = 3 × 7 = 21 unit Remaining work = 36 – 21 = 15 Remaining work completed by B = 15/3 = 5 days
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