Question
A task can be completed in 10 days by a team of 6 men
and 8 boys. The same task can also be completed in 2 days by 26 men and 48 boys. How long will it take for a group consisting of 15 men and 20 boys to complete the same task?Solution
Let efficiency of a men and a boy is ‘x’ units per day and ‘y’ units per day.
According to question:
(6x + 8y) × 10 = (26x + 48y) × 2
30x + 40y = 26x + 48y
4x = 8y
x = 2y
Total work = (6x + 8y) × 10 = 20y × 10 = 200y units
Efficiency of 15 men and 20 boys = 15x + 20y = 50y per day
Require time = 200y/50y = 4 days
More Time and work Questions
7292/3 = ?
7, 8, 12, 21, 37, ?
√4096 + 4/5 of 780 − ? = 296
- What will come in place of the question mark (?) in the following questions?
(2⁴ + 6²) ÷ 2 = ? - Simplify:
Simplify the following expression
What will come in the place of question mark (?) in the given expression?
{(2/15) + (12/25)} of 375 + 190 = ?% of 375
32% of 4080 + 24% of 540 = ? % of 3200
Simplify: 0.004 × 0.5
Relevant for Exams:
