Question
A and B together, B and C together and A and C
together can complete a piece of work in 12 days, 11 days and 12 days respectively. Find the ratio of the efficiencies of A, B and C, respectively.Solution
Let, the total work be 132 units (LCM of 12, 11 and 12)
Amount of work done by A and B together in one day = 132/12 = 11 units
Amount of work done by B and C together in one day = 132/11 = 12 units
Amount of work done by A and C together in one day = 132/12 = 11 units
Amount of work done by A, B and C together in one day = (11 + 12 + 11)/2 = 17 units
Amount of work done by A alone in one day = 17 – 12 = 5 units
Amount of work done by B alone in one day = 17 – 11 = 6 units
Amount of work done by C alone in one day = 17 – 11 = 6 units
So the desired ratio = 5:6:6
More Time and work Questions
(√1157 + 10.15% of 159.89) × 4.85 + 150.25 = ? × 19.67
{(√2305) % of 74.69} × 15.21 - 27.89 × 44.88 + 45.12% of 2399.87
(9116.89 – 8024.89 + 902.95) × 14 = 1800 × ?
(124.99)² = ?
? * 4.89 = (410.15 ÷ 13.97) % of 6190 - 1342.77
181.87 ÷ 13.89 X 8.13 + ? = 11.852Â
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
180.25 × 14.995 ÷ √26 = ? × 5.985
1224.86% of √6399.98 = (399.99/4.99)% of (? ÷ 6.91 + 39.87)Â
24.11% of 249.99 + √143.97 ÷ 12.02 = ?