Question
A can complete a piece of work in 20 days, and B in 30
days. They work together for 6 days, after which A leaves. In how many more days will B finish the remaining work?Solution
ATQ,
A’s 1 day work = 1/20, B’s = 1/30 Together 1 day = (1/20 + 1/30) = 1/12 Work done in 6 days = 6/12 = ½ Remaining = ½ B alone = (½) ÷ (1/30) = 15 days
More Time and work Questions
If cosB = sin(1.5B - 15°), then find the measure of 'B'.
- If sin A = 1/2, then what will be the value of cot² A?
If 2cosA + secA = 2√2 , 0° < < 90°, then the value of 2(sec 4 A + cosec 4 A) is:
If cos θ + sec θ = √5, then the value of cos³ θ+ sec³ θ is:
Find the value of sin 30°.
If X = 15°, find the value of:
sin²(4X) + cos²(3X) - tan²(2X)- If sin 2a = (3/4), then find the value of (sin a + cos a).
- If sin 2a = (1/2), then find the value of (sin a + cos a).
If 10sin²x + 6cos²x − 8 = 0, then find the value of sinx, given that 0° < x < 90°.
Relevant for Exams:
