Question
A can complete a piece of work in 20 days, and B in 30 days. They work together for 6 days, after which A leaves. In how many more days will B finish the remaining work?
Solution
ATQ,
A’s 1 day work = 1/20, B’s = 1/30 Together 1 day = (1/20 + 1/30) = 1/12 Work done in 6 days = 6/12 = ½ Remaining = ½ B alone = (½) ÷ (1/30) = 15 days
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