Question
Sheila walks at the speed of her usual speed (20/21) and
determines a clear distance in eight minutes more than the time it takes in normal speed. Calculate the normal time it takes to determine a certain distance.Solution
Let the speed of the Sheila be 21 unit Speed of the Sheila after decrement = 21 x 20/21 = 20 unit Speed ratio = 21: 20 Time ratio = 20:21 ... [... Time taken is inversely proportional to speed] 21-21= 1 unit ATQ- 1 unit =8 min 20unit = 8 x 20 = 160 min The total time taken by Sheila at the usual speed was 160 min.
105   107   111   114   ?   127
8 6 2 ? -1 9.5
...64Â Â Â 48Â Â Â 36Â Â Â 22Â Â Â Â 16Â Â Â Â 8
(45)2 ÷ ∛729 + (35)2 ÷ 1.4 =?
24, 33, 50, ?, 108, 149
16 4 2 1.5 1 1.875
...Find the wrong number in the given series.
3 1.5 1.5 ? 4.5 11.25
...18Â Â Â Â Â Â Â Â Â Â 434Â Â Â Â Â Â Â Â 642Â Â Â Â Â Â Â Â 746Â Â Â Â Â Â Â Â 798Â Â Â Â Â Â Â Â ?
...720    ?     240     180      144     120
...If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...
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