Question
A is cycling at an average speed of 48 km/hr such that
he can reach a certain point at 12 noon. If he cycles at 80 km/hr, then he will reach the destination at 10 a.m. At what speed he should cycle to reach the destination at 11 a.m.Solution
Let the distance to be travelled be βxβ km Time taken when speed is 48 km/hr = (x/48) hours Time taken when speed is 80 km/hr = (x/80) hours According to the question, (x/48) β (x/80) = 2 Or, 5x β 3x = 2 Γ 240 Or, x = 240 km Time taken to travel 240 km with speed of 48 km/hr = 240/48 = 5 hours Therefore, he started at 12 β 5 = 7 a.m. Therefore, required speed to reach the destination at 11 a.m. or 4 hours = 240/4 = 60 km/hr
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