Question
A is cycling at an average speed of 24 km/hr such that
he can reach a certain point at 12 noon. If he cycles at 36 km/hr, then he will reach the destination at 10 a.m. At what speed he should cycle to reach the destination at 11 a.m.Solution
Let the distance to be travelled be ‘x’ km Time taken when speed is 24 km/hr = (x/24) hours Time taken when speed is 36 km/hr = (x/36) hours According to the question, (x/24) – (x/36) = 2 Or, 3x – 2x = 2 × 72 Or, x = 144 km Time taken to travel 144 km with speed of 24 km/hr = 144/24 = 6 hours Therefore, he started at 12 – 6 = 6 a.m. Therefore, required speed to reach the destination at 11 a.m. or 4 hours = 144/5 = 28.8 km/hr
105   107   111   114   ?   127
8 6 2 ? -1 9.5
...64Â Â Â 48Â Â Â 36Â Â Â 22Â Â Â Â 16Â Â Â Â 8
(45)2 ÷ ∛729 + (35)2 ÷ 1.4 =?
24, 33, 50, ?, 108, 149
16 4 2 1.5 1 1.875
...Find the wrong number in the given series.
3 1.5 1.5 ? 4.5 11.25
...18Â Â Â Â Â Â Â Â Â Â 434Â Â Â Â Â Â Â Â 642Â Â Â Â Â Â Â Â 746Â Â Â Â Â Â Â Â 798Â Â Â Â Â Â Â Â ?
...720    ?     240     180      144     120
...If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...
