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Let the distance to be travelled be ‘x’ km Time taken when speed is 24 km/hr = (x/24) hours Time taken when speed is 36 km/hr = (x/36) hours According to the question, (x/24) – (x/36) = 2 Or, 3x – 2x = 2 × 72 Or, x = 144 km Time taken to travel 144 km with speed of 24 km/hr = 144/24 = 6 hours Therefore, he started at 12 – 6 = 6 a.m. Therefore, required speed to reach the destination at 11 a.m. or 4 hours = 144/5 = 28.8 km/hr
2/5 of 3/4 of 7/9 of 7200 = ?
16 × ? + 36% of 250 = 410
808 ÷ (128)1/7 + 482 = 4 × ? + 846
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
`(21 xx 51 + 54)/(9 xx 14 - 30 )` =?
12.232 + 29.98% of 539.99 = ? × 5.99
? = 120% of (652 ÷ 132 ) + 33 × 8
√? + √1296 + √729 = 464/4
The value of ((0.27)2-(0.13)2) / (0.27 + 0.13) is:
I. x² + 3x – 154 = 0
II. y² + 5y – 126 = 0