Question
If a car runs at 30 km/hr, it reaches its destination
late by 14 minutes but if runs at 40 km/hr it is late by 9 minutes. What is the correct time for the journey? PTSolution
Distance = Difference in time x (S1 x S2)/(S1 β S2) D = [14 β 9]/60 x {(40 x 30)/[40 β 30]} => (5/60) x (40 x 30)/10 => 10 km Time, T = D/S (take any one of the speed) => 10/30 = 10/30 x 60 = 20 minutes Then, correct time is 20 β 14 = 6 minutes
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