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    Question

    I. 7x² + 27x + 18 = 0 II. 19y² - 27y +

    8 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer
    A If x ≥ y Correct Answer Incorrect Answer
    B If x ≤ y Correct Answer Incorrect Answer
    C If x > y Correct Answer Incorrect Answer
    D If x < y Correct Answer Incorrect Answer
    E If x = y or relationship between x and y cannot be established Correct Answer Incorrect Answer

    Solution

    I. 7x² + 27x + 18 = 0 7x² + 21x + 6 x + 18 = 0 7x(x + 3) + 6 (x + 3) = 0 (7x + 6) (x + 3) = 0 x = -6/7 , - 3 II. 19y² - 27y + 8 = 0 19y² - 19y - 8 y + 8 = 0 19y(y – 1) – 8(y – 1) = 0 (y – 1)(19 y – 8) = 0 y = 1, 8/19 Hence, x < y

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