Question
I. 15y2 + 4y – 4 = 0 II.
15x2 + x – 6 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 15y2 + 4y – 4 = 0 15y2 + 10y – 6 y – 4 = 0 5y(3y + 2) – 2 (3 y + 2) = 0 (5 y – 2) (3 y + 2) = 0 y = 2/5, -2/3 II. 15x2 + x – 6 = 0 15x2 – 9 x + 10x – 6 = 0 3 x(5 x – 3) + 2 (5 x – 3) = 0 (3 x + 2) (5 x – 3) = 0 x = - 2/3, 3/5 Hence, x ≥ y
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