Question
I. x ² + 5 x + 6 =
0                 II. y²+ 7 y + 12= 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer if ;Solution
I. x ² + 5 x + 6 = 0 ( x + 3) ( x + 2) = 0 x = -3, -2 II.  y²+ 7 y + 12= 0 ( y + 4) ( y + 3) = 0 y = -3, -4 Hence, x ≥ y Â
- If, 4x + 3y = 18, and 2xy = 12, and 4x > 3y, then find the value of 64x 3 Â - 27y 3 .
If the ratio of the areas of two triangles is 4:3 and the ratio of their heights is 3:4, then the ratio of the lengths of their bases will be
A sum of Rs. 25,000 is invested in SIP 'G' which offers 7% p.a. simple interest for 7 years. The interest received from SIP 'G' is invested in SIP 'H' w...
189500 – 22650 + 48× ? – 352×18 = 162674
If ab = -15 and (a2 + b2) = 34, then find the value of (a – b).
Average marks scored by Vineet in five subjects are 60. The average marks scored by him (excluding his highest and lowest marks) are 50 and lowest marks...
If the length of a rectangle is increased by 40%, and the breadth is decreased by 20%,then the area of the rectangle increases by x%. Then the value of ...
If 512x3 - y3 = (8x - Ay) X (Bx2 + y2 + Cxy), then find the value of 3 X (2A + 6B) - 2C.
If (p/q) = (7/8) and (q/r) = (3/11), then the find the value of {(r – p)/(p + q)}.