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    Question

    I. 6y2 – 23y + 20 = 0 II.

    4x2 – 24 x + 35 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A If x > y Correct Answer Incorrect Answer
    B If x тЙе y Correct Answer Incorrect Answer
    C If x < y Correct Answer Incorrect Answer
    D If x тЙд y Correct Answer Incorrect Answer
    E If x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 6y2 – 23y + 20 = 0 6y2 – 8y – 15 y + 20 = 0 2y (3 y – 4) – 5 (3 y – 4) = 0 (2 y – 5) (3 y – 4) = 0 y = 5/2 ,4/3 II. 4x2 – 24 x + 35 = 0 4x2 – 14 x – 10 x + 35 = 0 2 x(2 x – 7) – 5 (2 x – 7) = 0 (2 x – 5) (2 x – 7) = 0 x = 5/2 ,7/2 Hence, x≥y

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