Question
I. 2x2 – 19x + 45 = 0 II.
y2 – 14y + 48 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer:Solution
I. 2x2 – 19x + 45 = 0 => 2x2 – 10x – 9x + 45 = 0 => 2x(x – 5) – 9(x – 5) = 0 => (x – 5) (2x – 9) = 0 => x = 5, 4.5 II. y2 – 14y + 48 = 0 => y2 – 8y – 6y + 48 = 0 => y(y – 8) – 6(y – 8) = 0 => (y – 8) (y – 6) = 0 => y = 8, 6 Hence, x < y.
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