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    Question

    I. 2x2 – 19x + 45 = 0 II.

    y2 – 14y + 48 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer:
    A if x < y Correct Answer Incorrect Answer
    B if x ≥ y Correct Answer Incorrect Answer
    C if x > y Correct Answer Incorrect Answer
    D if x ≤ y Correct Answer Incorrect Answer
    E if x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 2x2 – 19x + 45 = 0 => 2x2 – 10x – 9x + 45 = 0 => 2x(x – 5) – 9(x – 5) = 0  => (x – 5) (2x – 9) = 0 => x = 5, 4.5 II. y2 – 14y + 48 = 0 => y2 – 8y – 6y + 48 = 0 => y(y – 8) – 6(y – 8) = 0 => (y – 8) (y – 6) = 0 => y = 8, 6 Hence, x < y.

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