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      Question

      I. 2y2 + 31y + 99 = 0 II.

      4x2 + 8x – 45 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
      A If x > y Correct Answer Incorrect Answer
      B If x ≥ y Correct Answer Incorrect Answer
      C If x < y Correct Answer Incorrect Answer
      D If x ≤ y Correct Answer Incorrect Answer
      E If x = y or the relationship cannot be established Correct Answer Incorrect Answer

      Solution

      I. 2y2 + 31y + 99 = 0 2y2 + 9y + 22 y + 99 = 0 y (2 y + 9) + 11(2 y + 9) = 0 (y + 11) (2 y + 9) = 0 y = -11, -9/2 II. 4x2 + 8x – 45 = 0 4x2 - 10x - 18 x – 45 = 0 2x(2 x - 5) + 9(2 x – 5) = 0 (2x + 9) (2 x – 5) = 0 x = - 9/2,5/2 Hence x = y or the relationship cannot be established

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