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    Question

    I. 15y2 + 26y + 8 = 0 II.

    20x2 + 7x – 6 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A If x > y Correct Answer Incorrect Answer
    B If x ≥ y Correct Answer Incorrect Answer
    C If x < y Correct Answer Incorrect Answer
    D If x ≤ y Correct Answer Incorrect Answer
    E If x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 15y2 + 26y + 8 = 0 15y2 + 6y + 20 y + 8 = 0 3 y (5 y + 2) + 4 (5 y + 2) = 0 (3 y + 4) (5 y + 2) = 0 y = -4/3,-2/5 II. 20x2 + 7x – 6 = 0 20x2 + 15x - 8 x – 6 = 0 5 x(4 x + 3) – 2(4 x + 3) = 0 x = 2/5,-3/4 Hence, no relationship cannot be established between x and y

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