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ATQ,From I: p2 – 3p – 54 = 0 p2 – 9p + 6p – 54 = 0 p(p – 9) + 6(p – 9) = 0 (p – 9)(p + 6) = 0 p = 9, -6 From II: q2– 19q + 90 = 0 q2– 9q – 10q + 90 = 0 q(q – 9) – 10(q – 9) = 0 (q –9)(q – 10) = 0 q = 9, 10 So, p ≤ q
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