Question
I. 2x2 – 5x – 12 = 0 II.
2y2 + 13y + 20 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 2x2 – 5x – 12 = 0 2x2 + 3 x – 8x – 12 = 0 x (2 x + 3) – 4 (2 x + 3) = 0 (x – 4) (2 x + 3) = 0 x = 4, – 3/2 II. 2y2 + 13y + 20 = 0 2y2 + 5y + 8 y + 20 = 0 y (2 y + 5) + 4(2 y + 5) = 0 (y + 4) (2 y + 5) = 0 y = – 4, -5/2 Hence, x>y
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