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    Question

    I. 2x2 – 5x – 12 = 0 II.

    2y2 + 13y + 20 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A If x > y Correct Answer Incorrect Answer
    B If x тЙе y Correct Answer Incorrect Answer
    C If x < y Correct Answer Incorrect Answer
    D If x тЙд y Correct Answer Incorrect Answer
    E If x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 2x2 – 5x – 12 = 0 2x2 + 3 x – 8x – 12 = 0 x (2 x + 3) – 4 (2 x + 3) = 0 (x – 4) (2 x + 3) = 0 x = 4, – 3/2 II. 2y2 + 13y + 20 = 0 2y2 + 5y + 8 y + 20 = 0 y (2 y + 5) + 4(2 y + 5) = 0 (y + 4) (2 y + 5) = 0 y = – 4, -5/2 Hence, x>y

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