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      Question

      Solve the quadratic equations and determine the relation

      between x and y: Equation 1: 97x² - 436x + 339 = 0 Equation 2: 103y² - 460y + 357 = 0
      A x > y Correct Answer Incorrect Answer
      B x ≥ y Correct Answer Incorrect Answer
      C x < y Correct Answer Incorrect Answer
      D x ≤ y Correct Answer Incorrect Answer
      E x = y or no relation Correct Answer Incorrect Answer

      Solution

      From Equation 1: 97x² - 436x + 339 = 0 Factorizing: (97x - 339)(x - 1) = 0 So, x = 339/97 or x = 1. From Equation 2: 103y² - 460y + 357 = 0 Factorizing: (103y - 357)(y - 1) = 0 So, y = 357/103 or y = 1. Comparing x and y: x = 339/97, y = 1, x > y x = 1, y = 357/103, x < y x = 1, y = 1, x = y Correct option: E) x = y or no relation

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