Question
Solve the quadratic equations and determine the relation
between x and y: Equation 1: 97x² - 436x + 339 = 0 Equation 2: 103y² - 460y + 357 = 0Solution
From Equation 1: 97x² - 436x + 339 = 0 Factorizing: (97x - 339)(x - 1) = 0 So, x = 339/97 or x = 1. From Equation 2: 103y² - 460y + 357 = 0 Factorizing: (103y - 357)(y - 1) = 0 So, y = 357/103 or y = 1. Comparing x and y: x = 339/97, y = 1, x > y x = 1, y = 357/103, x < y x = 1, y = 1, x = y Correct option: E) x = y or no relation
(i) 2x² – 12x + 16 = 0
(ii) 2y² – 20y + 48 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
Solve: 3x² − 7x − 6 = 0
I. 5x + 2y = 31
II. 3x + 7y = 36
What is the average salary of 10 officers , if a clerk’s salary is Rs. 15,000?
Statement I: The total salary of 10 officers and 5 clerk is Rs....
For what values of k does the equation x² – (k+1)x + k = 0 have two distinct real roots, both greater than 1?
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
I. 25p + 2(2p2 – 1) = 8(p + 5)
II. 8q2 + 35q – 78 = 0
I. x2 + 24x + 143 = 0
II. y2 + 12y + 35 = 0
I. 2x² - 12x + 16 = 0  Â
II. 4y² - 8y - 12 = 0  Â
