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    Question

    I. 3y² - 20y + 25 = 0 II. 3x² - 8x + 5

    = 0
    A if x > y Correct Answer Incorrect Answer
    B if x тЙе y Correct Answer Incorrect Answer
    C if x < y Correct Answer Incorrect Answer
    D if x тЙд y Correct Answer Incorrect Answer
    E if x = y or the relationship cannot be established. Correct Answer Incorrect Answer

    Solution

    I. 3y² - 20y + 25 = 0 3y² - 15y - 5y + 25 = 0 3y (y – 5) – 5 (y – 5) = 0 (3y – 5) (y – 5) = 0 y = 5, 5/3 II. 3x² - 8x + 5 = 0 3x² - 5x - 3x + 5 = 0 (x – 1) (3x – 5) = 0 x = 1, 5/3 Hence, x ≤ y

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