Question
A 120-litre mixture contains 25% alcohol. How many
litres of alcohol should be added so that alcohol becomes 40% of the final mixture?Solution
ATQ,
Initial quantity of alcohol = 0.25 × 120 = 30 litres Let the required alcohol to add = y litres So, (30 + y) ÷ (120 + y) = 40/100 = 2/5 ⇒ 5(30 + y) = 2(120 + y) ⇒ 150 + 5y = 240 + 2y ⇒ 3y = 90 ⇒ y = 30
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