Container A contains a mixture of milk and water in the ratio 4 : 1 respectively. Container B contains a mixture of milk, water and sugar in the ratio 3 : 2 : 1 respectively. When the mixtures from both containers are combined, the final quantities of milk and water are 128 liters and 52 liters respectively. Find the quantity of sugar in the final mixture.

ATQ, In Container A, milk and water are in the ratio 4 : 1. Let the quantities of milk and water in Container A be 4a and 1a. In Container B, milk, water and sugar are in the ratio 3 : 2 : 1. Let the quantities of milk, water and sugar in Container B be 3b, 2b and 1b. Final quantity of milk = 128 liters. So, 4a + 3b = 128 Final quantity of water = 52 liters. So, a + 2b = 52 From a + 2b = 52: a = 52 − 2b Put a = 52 − 2b in 4a + 3b = 128: 4(52 − 2b) + 3b = 128 208 − 8b + 3b = 128 208 − 5b = 128 5b = 208 − 128 5b = 80 b = 80/5 b = 16 Quantity of sugar in final mixture = 1b Sugar = 1 × 16 = 16 liters