Ratio of copper to tin in the alloy = 3:2 Let the quantity of copper and tin in the alloy be 3x kg and 2x kg, respectively. According to question, 3x = 2x + 10 x = 10 kg So, the quantity of new alloy = 3x + 2x + 10 = 5x + 10 ⇒ 50 + 10 = 60 kg
2 X 25 + (30% of 80) ÷ (10% of 120) = ?
?2 = √20.25 × 10 + √16 + 32
{(123 + ? × 28) – 1254} × (2328 ÷ 97 – 13) = 8195
36.76 + 2894.713 + 34965.11 =?
20.5 × 36 + 24 × 8 + ?2 = 1954
24% of 400 × 16% of ? = 384
756 + 432 – 361 + ? = 990
√4096 + √3249 = (?)2
25.6% of 250 + √? = 119
28 + √144 + 144 ÷ (3)2 = ? - 4
