Question
The average of four numbers is 150. Two of the numbers
are equal (not least), and 50 more than the least number. If the 4th number is twice the least number then find the average of smallest and largest number.Solution
ATQ, Let the two equal numbers be ‘b’ each Therefore, least number = (b – 50) 4th number = 2(b – 50) According to the question, 2(b – 50) + b – 50 + b + b = 4 × 150 Or, 5b – 150 = 600 Or, b = 750/5 = 150 Therefore, 4 numbers are 150, 150, 100, and 200 Therefore, required average = (200 + 100)/2 = 150
612, 487,?, 396, 388, 387
Find the missing number in the given number series.
1, 2, 6, 24, 120, ?What will come in place of the question mark (?) in the following series?
36, 85, ?, 230, 330, 451
Find the missing term in the series:
2, 5, 11, 23, 47, ?
What will come in place of the question mark (?) in the following series?
400, 841, 1202, ?, 1716, 1885
44   45    41   50    ?      59    23
...221, 100, 0, -81, ?
...900 Â Â Â 90Â Â Â 18Â Â Â ? Â Â Â Â 2.16Â Â Â Â 1.08
16, 20, 11, 27, ?, 38
37, 57, 82, ?, 147, 187
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