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      Question

      The average of four numbers is 150. Two of the numbers

      are equal (not least), and 50 more than the least number. If the 4th number is twice the least number then find the average of smallest and largest number.
      A 120 Correct Answer Incorrect Answer
      B 150 Correct Answer Incorrect Answer
      C 180 Correct Answer Incorrect Answer
      D 110 Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      ATQ, Let the two equal numbers be ‘b’ each Therefore, least number = (b – 50) 4th number = 2(b – 50) According to the question, 2(b – 50) + b – 50 + b + b = 4 × 150 Or, 5b – 150 = 600 Or, b = 750/5 = 150 Therefore, 4 numbers are 150, 150, 100, and 200 Therefore, required average = (200 + 100)/2 = 150

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