The average weight of five friends A, B, C, D and E is (x+5) years while the average weight of C and E is (x-5) kg. If the weight of another person F is also added, then average weight of all of them is reduced by 6 kg. Find the value of ‘x’ if average weight of A, B, D and F is 96 kg.
Total weight of friends A, B, C, D and E = 5(x+5) kg So, Total weight of A, B and D = 5(x+5) – 2(x-5) = (3x+35) kg Weight of F = [(x+5-6)×6] - [5(x+5)] => F = (x-31) kg According to the question, => (3x+35) + (x-31) = 96 × 4 => 4x + 4 = 384 => 4x = 380 => x = 95
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