📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

  • google app store apple app store
  • ✖

      Question

      The average weight of five friends A, B, C, D and E is

      (x+5) years while the average weight of C and E is (x-5) kg. If the weight of another person F is also added, then average weight of all of them is reduced by 6 kg. Find the value of ‘x’ if average weight of A, B, D and F is 96 kg.
      A 74 kg Correct Answer Incorrect Answer
      B 80 kg Correct Answer Incorrect Answer
      C 83 kg Correct Answer Incorrect Answer
      D 90 kg Correct Answer Incorrect Answer
      E 95 kg Correct Answer Incorrect Answer

      Solution

      Total weight of friends A, B, C, D and E = 5(x+5) kg So, Total weight of A, B and D = 5(x+5) – 2(x-5) = (3x+35) kg Weight of F = [(x+5-6)×6]  -  [5(x+5)] => F = (x-31) kg According to the question, => (3x+35) + (x-31) = 96 × 4 => 4x + 4 = 384 => 4x = 380 => x = 95

      Practice Next
      ask-question