Question
The average weight of five friends A, B, C, D and E is
(x+8) years while the average weight of C and E is (x-8) kg. If the weight of another person F is also added, then average weight of all of them is reduced by 7 kg. Find the value of ‘x’ if average weight of A, B, D and F is 92.5 kg.Solution
Total weight of friends A, B, C, D and E = 5(x+8) kg So, Total weight of A, B and D = 5(x+8) - 2(x-8) = (3x+56) kg Weight of F = [(x+8-7)×6] - [5(x+8)] => F = (x-34) kg According to the question, => (3x+56) + (x-34) = 92.5 × 4 => 4x + 22 = 370 => 4x = 348 => x = 87
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will replace the question mark (?) in the following?
18.99...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will replace the question mark (?) in the following?
19.99...
(34.03 + 101.98) ÷ 17.211 = 89.9 – 25.23% of ?
? + 165.99 – 104.01 = 26.01 × 7.98
(13.13 ×  32.98) + 20.15% of 649.99 = ? + 122.34
{(1799.89 ÷ 8.18) ÷ 9.09 + 175.15} = 25.05% of ?
A Sales Executive gets a commission on total sales at 10%. If the sale is exceeded Rs.15,000 he gets an additional commission as a bonus of 5% on the ex...
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