Question
An alloy of copper and tin contains 85% of copper. If 28
kg of more tin is added to the alloy, the copper content gets reduced to 50%. Find the quantity of the new alloy.Solution
Ratio of copper to tin in the alloy = 17:3 Let the quantity of copper and tin in the alloy be 17x kg and 3x kg, respectively. According to question, 17x = 3x + 28 x = 2 kg So, the quantity of new alloy = 17x + 3x + 28 = 20x + 28 ⇒ 40 + 28 = 68 kg
612 + 1250 - 728 = ? × 63
What will come in the place of question mark (?) in the given expression?
45% of (√6400 × 5) = ? + 111
(34.88% of 699.79) + 40.030 × 17.88 of 11.86 + 16.21 =? + (7.22)²
(√ 121 x 41) + (3√343 x √289 ) = ? x 19
?2 = (1035 ÷ 23) × (1080 ÷ 24)
(3984 ÷ 24) x (5862 ÷ 40) = ?
√ [? x 11 + (√ 1296)] = 16
If 840 ÷ 12 + 1025 ÷ 25 - n + 45 × 4 = 960 ÷ 16 × 132 ÷ 44, then the value of n is:
7/11 × 1034 + 1(4/7) × 2401 = 1230 +?
95% of 830 - ? % of 2770 = 650