Question
In solution A, the ratio of mixtures P to Q is 5:3,
while in solution B, the ratio of mixtures P to Q is 3:2. If 50% of solution A is added to solution B, the difference between the amounts of P and Q in solution B increases by 30 liters. Given that the total volume of solution A is 80 liters, determine the new ratio of mixture X to Y in solution B.Solution
ATQ,
Mixture P in solution A = 80 *5/8 = 50 Mixture Q in solution A = 80 – 50 = 30 50% of solution transferred => 50 * 1/2 = 25 litres of Mixture P 30 * 1/2 = 15 litres of Mixture Q (3x + 25) – (2x + 15) = 30 x + 10 = 30 x = 20 Required ratio = (3*20) + 25 : (2*20) + 15 = 85 : 55 = 17 : 11
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