Question
Average speed of ‘A’ during a 24-hour journey is 38
km/h. If he covered the first 120 km of his journey at a speed of 20 km/h, then find the speed at which ‘A’ travelled during the remaining journey.Solution
Total distance covered by ‘A’ = 24 × 38 = 912 km Time taken to cover 120 km = 120/20 = 6 hours Time taken to cover remaining distance = 24 – 6 = 18 hours So, required speed = {(912 – 120)/18} = 44 km/h
More ESIC Part B Questions
Simplify the expression:
(9x² - 25) / (3x + 5)
√? × 4 - 374 + 127 + 300 = 117
Find the simplified value of the following expression:
14.25 × 32 – 11.4 × 15 + 8 – 712 ÷ 8 + 34.15 × 20 – 27 × 21 = ?
...- 55% of 220 – 15% of 40 = 20% of ?
(21 X 5) + ? = (480 - 120) ÷ 3
125 + 30% of 250 + √576 = ?
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
Find the simplified value of the given expression:
8 of 7 ÷ 2 × 5² + √36 – 10216% of 350 + 273 = ?2 × 21
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