Question
Pipe ‘E’ alone can fill a tank in 15 hours. When
pipe ‘E’ and ‘F’ are opened together, they can fill 90% of the same tank in 9 hours. Find the time taken by pipe ‘F’ alone to fill 40% of the same tank.Solution
ATQ; Time taken by pipes ‘E’ and ‘F’ together to fill 100% of the tank = 9 ÷ 0.9 = 10 hours Let the capacity of the tank be 60 litres. {LCM (15 and 10)} Efficiency of pipe ‘E’ = (60/15) = 4 litres/hour Efficiency of pipe ‘E’ and ‘F’ together = (60/10) = 6 litres/hour Efficiency of pipe ‘F’ = 6 – 4 = 2 litres/hour Time taken by pipe ‘F’ to fill 40% of the tank = (60 × 0.4)/2 = 12 hours
Determine the sum of the first 16 odd numbers.
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The remainder obtained when (47³ + 35³) is divided by 41 isÂ
16Â Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â Â Â Â Â 1.5Â Â Â Â Â Â Â Â Â 1Â Â Â Â Â Â Â Â Â Â Â Â Â 1.875
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