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    Question

    An alloy ‘M’ contains lead and iron in the ratio 4:3,

    and alloy ‘N’ contains iron and copper in the ratio 2:5. If 35 grams of ‘M’ and 42 grams of ‘N’ are combined, determine the final ratio of lead, iron and copper respectively.
    A 5:15:16 Correct Answer Incorrect Answer
    B 20:27:30 Correct Answer Incorrect Answer
    C 19:12:21 Correct Answer Incorrect Answer
    D 16:15:6 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Weight of lead in 35 grams of 'M' = 35 × (4/7) = 20 grams

    So, weight of iron in 35 grams of 'M' = 35 − 20 = 15 grams

    Weight of iron in 42 grams of 'N' = 42 × (2/7) = 12 grams

    So, weight of copper in 42 grams of 'N' = 42 − 12 = 30 grams

    So, total weight of iron = 15 + 12 = 27 grams

    So, required ratio = 20:27:30 = 20:27:30

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