📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!
  • google app store apple app store
    • ✖

      Question

      An alloy ‘M’ contains lead and iron in the ratio 4:3,

      and alloy ‘N’ contains iron and copper in the ratio 2:5. If 35 grams of ‘M’ and 42 grams of ‘N’ are combined, determine the final ratio of lead, iron and copper respectively.
      A 5:15:16 Correct Answer Incorrect Answer
      B 20:27:30 Correct Answer Incorrect Answer
      C 19:12:21 Correct Answer Incorrect Answer
      D 16:15:6 Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      ATQ,

      Weight of lead in 35 grams of 'M' = 35 × (4/7) = 20 grams

      So, weight of iron in 35 grams of 'M' = 35 − 20 = 15 grams

      Weight of iron in 42 grams of 'N' = 42 × (2/7) = 12 grams

      So, weight of copper in 42 grams of 'N' = 42 − 12 = 30 grams

      So, total weight of iron = 15 + 12 = 27 grams

      So, required ratio = 20:27:30 = 20:27:30

      Practice Next
      More Mixture Questions

      Relevant for Exams:

      ask-question