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    Question

    Alloy ‘P’ has aluminium and nickel in a 7:9 ratio.

    Alloy ‘Q’ is made up of nickel and zinc in a 4:6 ratio. If 48 grams of ‘P’ and 60 grams of ‘Q’ are fused, what will be the resulting ratio of aluminium, nickel and zinc respectively?
    A 5:15:16 Correct Answer Incorrect Answer
    B 7:17:12 Correct Answer Incorrect Answer
    C 19:12:21 Correct Answer Incorrect Answer
    D 16:15:6 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Weight of aluminium in 48 grams of 'P' = 48 × (7/16) = 21 grams

    So, weight of nickel in 48 grams of 'P' = 48 − 21 = 27 grams

    Weight of nickel in 60 grams of 'Q' = 60 × (4/10) = 24 grams

    So, weight of zinc in 60 grams of 'Q' = 60 − 24 = 36 grams

    So, total weight of nickel = 27 + 24 = 51 grams

    So, required ratio = 21:51:36 = 7:17:12

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