Question
Metal mixture ‘C’ consists of mercury and platinum in
the ratio 2:3. Another alloy ‘D’ includes platinum and titanium in the ratio 1:4. If 25 grams of ‘C’ and 50 grams of ‘D’ are mixed, what is the final ratio of mercury, platinum and titanium?Solution
ATQ,
Weight of mercury in 25 grams of 'C' = 25 × (2/5) = 10 grams
So, weight of platinum in 25 grams of 'C' = 25 − 10 = 15 grams
Weight of platinum in 50 grams of 'D' = 50 × (1/5) = 10 grams
So, weight of titanium in 50 grams of 'D' = 50 − 10 = 40 grams
So, total weight of platinum = 15 + 10 = 25 grams
So, required ratio = 10:25:40 = 2:5:8
In Which of the following expressions does the expression ‘ H ≥ D ’ definitely hold true?
Statements: M % N, N & A, A @ B, B # C
Conclusions: I. C & A II. M # B
...Statements: A < B; C = D; B >E ≥ C
Conclusions:
I. A < C
II. E = D
Statements: C > D ≥ E > F; H ≥ G < F; I > H
Conclusions:
I. C > I
II. D > G
III. C ≤ HStatements : I = K > N; N ≥ G ≥ H; P = H > F = O
Conclusions :
I. F < K
II. P ≤ N
III. I > P
Statements: M = R ≥ S , N = O > Q, Q > W = A < S
Conclusions :I. N ≥ S II. W > R III. O ≤ S
Statements: X ≥ Y= Z ≤ A, K < A ≤ M < W
Conclusion:
I. M = Y
II. M > Y
III. K ≤ Y
- Statements: X < H = U ≤ I < N = M, M > B ≥ V
Conclusions:
I. I > V
II. U ≥ M Statements: T = S, U ≤ V, P < K, U ≤ K, V > S
Conclusion:
I. S ≥ U
II. S < U
Statements: T ≥ U = V > W = Z ≤ X < Y ≤ M
Conclusions:
I. Z > T
II. U ≤ X