Question
Metal mixture ‘C’ consists of mercury and platinum in
the ratio 2:3. Another alloy ‘D’ includes platinum and titanium in the ratio 1:4. If 25 grams of ‘C’ and 50 grams of ‘D’ are mixed, what is the final ratio of mercury, platinum and titanium?Solution
ATQ,
Weight of mercury in 25 grams of 'C' = 25 × (2/5) = 10 grams
So, weight of platinum in 25 grams of 'C' = 25 − 10 = 15 grams
Weight of platinum in 50 grams of 'D' = 50 × (1/5) = 10 grams
So, weight of titanium in 50 grams of 'D' = 50 − 10 = 40 grams
So, total weight of platinum = 15 + 10 = 25 grams
So, required ratio = 10:25:40 = 2:5:8
By interchanging the given two signs and numbers which of the following equation will be correct?
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