Question
There are three distinct numbers ‘x’, ‘y’ and
‘z’. If, x = 180, (x + y) = 480 and (z – y) = 60, then find the average of x, y and z.Solution
Given, x = 180, (x + y) = 480 and (z – y) = 60Therefore, y = 480 – 180 = 300And, z = 300 + 60 = 360Required average = (180 + 300 + 360)/3 = 840/3 = 280
20% of 1500 – 75% of 200 = 125% of ?
24% of 150% of 500 + 140 = ? × 8
458.32 - 563.32 + 659.32 =?
What will come in the place of question mark (?) in the given expression?
(√1089 + 84 ÷ 2) % of 348 = 416 - ?

40% are the passing marks. A student gets 250 marks yet fails by 38 marks. What is the maximum marks?
(22.5 × 24) ÷ 40 + 51.50 = ? ÷ 5.25
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
What will come in the place of question mark (?) in the given expression?
√64 X 9 ÷ 3 + 12 X 3 = ? + 36(3/7) x 868 + 25% of 240 = (? + 65)