Question
There are three distinct numbers ‘x’, ‘y’ and
‘z’. If, x = 180, (x + y) = 480 and (z – y) = 60, then find the average of x, y and z.Solution
Given, x = 180, (x + y) = 480 and (z – y) = 60Therefore, y = 480 – 180 = 300And, z = 300 + 60 = 360Required average = (180 + 300 + 360)/3 = 840/3 = 280
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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