Question
If (3cos A - sin
- A = 2 cos (90° -
- A , then find the value of cot A.
Solution
We have, (3cos A - sin A) = 2 cos (90° - A)
Or, (3cos A - sin A) = 2 sin A
Or, 3cos A = 3 sin A
Or, {(cos A)/(sin A)} = 1
So, cot A = 1
Hence, option a.
More Trigonometry Questions
- If cot A = 12/5, then the value of (sin A + cos A) × sec A is ________.
- If 1 + sin 2θ = p2 and sin3 θ + cos3 θ = q then Which of the following is true ? 1. q3 – 2p + 3q = 0 2. p3 – 3p + 2q = 0 3. q3 + 2p – 2q = 0 4. p3 – 2p + ...
- If acos 3 θ + 3asin 2 θcosθ = m and asin 3 θ + 3asinθcos 2 θ = n, then find the value of (m + n) 2/3 + (m – n) 2/3 .
- A tower is 60 meters high. From a point on the ground, the angle of elevation of the top of the tower is 30°. Find the distance of the point from the base ...
- If cos2B = sin(1.5B - 36 o ) , then find the measure of 'B'.
- Find the Value of Sin⁶`Theta` + Cos⁶`Theta` + 3Sin² `theta` Cos²`Theta`
- If (3cos A - sin A) = 2 cos (90° - A), then find the value of cot A.
- If 3cos²A + 2sin²A = 11/5, then find the value of (sec²A - 1)
- Simplify: 8sin 27° sec 63° + 3cot 64° cot 26°
- If x = r sin A cos B, y = r sin A sin B and z = r cos A, then find x² + y² + z².
