Question
If tanθ – cotθ = a and cosθ + sinθ = b, then
(b2 –1)(a2 + 4) = ?Solution
Put θ = 45°
then, a = tanθ – cotθ = 1 –1 = 0
and, b = cosθ + sinθ
= 1/√2 + 1/√2 =√2
Now, (b 2 –1) (a 2 + 4) = (2 – 1) (0 + 4) = 4
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