Answer-If sin (3A − 4B) = (1/2) and cos (A + B) = (√2/2), where 0° < A, B < 90°, then find the value of ‘A’...

Q: Answer-If sin (3A − 4B) = (1/2) and cos (A + B) = (√2/2), where 0° < A, B < 90°, then find the value of ‘A’...

sin 3A 4B 12 Or, sin 3A 4B sin 30 Or, 3A 4B 30 ----------- I And, cos A B 22 Or, cos A B cos 45 Or, A B 45 -------------- II On solving equation I 4 equation II, we get 3A 4B 4 A B 30 4 45 Or, 3A 4B 4A 4B 210 Or, 7A 210 So, A 30

Question

If sin (3A − 4

B = (1/2) and cos (A +
B = (√2/2), where 0° < A, B < 90°, then find the value of ‘A’.

A 30°

B 40°

C 20°

D 15°

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