Question
If sec 2A = sin2 60o + sec
60o - cos2 30 o , then find the value of (√3tan A + cot 2 A).Solution
sec 2A = sin 2 60 o + sec 60 o - cos 2 30 o
Or, sec 2A = (√3/2) 2 + sec 60 o - (√3/2) 2
Or, sec 2A = sec 60 o
Or, 2A = 60
Or, 'A' = 30
So, required value = √3 x tan 30 o + cot 2 30 o
= √3 x (1/√3) + (√3) 2 = 1 + 3 = 4
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