Question
If sec 2A = sin2  60o  + sec
60o  - cos2 30 o , then find the value of (√3tan A + cot 2  A).Solution
sec 2A = sin 2  60 o  + sec 60 o  - cos 2  30 o
Or, sec 2A = (√3/2) 2  + sec 60 o  - (√3/2) 2
Or, sec 2A = sec 60 o
Or, 2A = 60
Or, 'A' = 30
So, required value = √3 x tan 30 o  + cot 2  30 o
= √3 x (1/√3) + (√3) 2 = 1 + 3 = 4
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