Question

    If sec 2A = sin2  60o  + sec

    60o  - cos2 30 o , then find the value of (√3tan A + cot 2  A).
    A 4 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 1 Correct Answer Incorrect Answer
    D 3 Correct Answer Incorrect Answer

    Solution

    sec 2A = sin 2  60 o  + sec 60 o  - cos 2  30 o

    Or, sec 2A = (√3/2)  2  + sec 60 o  - (√3/2)  2

    Or, sec 2A = sec 60 o

    Or, 2A = 60

    Or, 'A' = 30

    So, required value = √3 x tan 30 o  + cot 2  30 o

    = √3 x (1/√3) + (√3)  2 = 1 + 3 = 4

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