Question
Simplify the following trigonometric expression:13cos
63 o cosec 27 o - 5cot 56 o cot 34 oSolution
13cos 63 o cosec 27 o - 5cot 56 o cot 34 o
= 13cos 63 o cosec (90 o - 63 o ) - 5cot 56 o cot (90 o - 56 o )
Using, cosec (90 - A) = sec A and cot (90 - A) = tan A
= 13cos 63 o sec 63 o - 5cot 56 o tan 56 o
Since, sec A is reciprocal of cos A and cot A is reciprocal of tan A.
= 13 - 5 = 8
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