Question
If sec 2P = sin² 60⁰ + sec 60⁰ - cos² 30⁰, then
determine the value of (√3tan P + cot² P)Solution
ATQ,
sec 2P = sin² 60⁰ + sec 60⁰- cos² 30⁰
Or, sec 2P = (√3/2)² + sec 60⁰- (√3/2)²
Or, sec 2P = sec 60⁰
Or, 2P = 60
Or, 'P' = 30
So, required value = √3 X tan 30⁰ + cot² 30⁰
= √3 X (1/√3) + (√3)²
= 1 + 3 = 4
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