Question
(tan 5x - tan 3x - tan 2x) = ?
Solution
tan (3x + 2x) = tan 5x β (tan3x + tan2x)/(1 - tan3x.tan2x) = tan 5x β (tan3x + tan2x) = tan 5x - tan3x..tan2x .tan 5x Above Question can also be written as β (tan 5x - (tan 3x + tan 2x) β (tan 5x - (tan 5x - tan3x..tan2x .tan 5x) β tan 5x - tan 5x + tan3x..tan2x .tan 5x tan3x..tan2x .tan 5x tan 2x tan 3x tan 5x
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (β 484 β β 256) = ?
(13)2Β - 3127 Γ· 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 Γ· 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 Γ 5 - {272 + 162 - 422}
(15 Γ 225) Γ· (45 Γ 5) + 480 = ? + 25% of 1240
β [? x 11 + (β 1296)] = 16
11 Γ 25 + 12 Γ 15 + 14 Γ 20 + 15 = ?