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      Question

      (tan 5x - tan 3x - tan 2x) = ?

      A tan 2x tan 3x tan 5x Correct Answer Incorrect Answer
      C tan 2x Sin 3x tan 5x Correct Answer Incorrect Answer
      D 17/7 Correct Answer Incorrect Answer

      Solution

      tan (3x + 2x) = tan 5x β‡’ (tan3x + tan2x)/(1 - tan3x.tan2x) = tan 5x β‡’ (tan3x + tan2x) = tan 5x - tan3x..tan2x .tan 5x Above Question can also be written as β‡’ (tan 5x - (tan 3x + tan 2x) β‡’ (tan 5x - (tan 5x - tan3x..tan2x .tan 5x) β‡’ tan 5x - tan 5x + tan3x..tan2x .tan 5x tan3x..tan2x .tan 5x tan 2x tan 3x tan 5x

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