Question
(tan 5x - tan 3x - tan 2x) = ?
Solution
tan (3x + 2x) = tan 5x ⇒ (tan3x + tan2x)/(1 - tan3x.tan2x) = tan 5x ⇒ (tan3x + tan2x) = tan 5x - tan3x..tan2x .tan 5x Above Question can also be written as ⇒ (tan 5x - (tan 3x + tan 2x) ⇒ (tan 5x - (tan 5x - tan3x..tan2x .tan 5x) ⇒ tan 5x - tan 5x + tan3x..tan2x .tan 5x tan3x..tan2x .tan 5x tan 2x tan 3x tan 5x
Statements: E & F, H # I, G $ F, E % D, G @ H
Conclusions:
I. D $ F
II. F @ I ...
Statements: I > O = D; K < J ≤ O; L > K ≥ S
Conclusions:
I. I > S
II. D ≥ L
III. S > O
Statements: I ≤ J = K < L < M, G ≥ H = I = T
Conclusions:
I. J > G
II. M = H
III. M > H
...Statements: J > K = N ≥ O = P ≥ Q, M < L ≤ Q
Conclusions:
I. O ≥ M
II. L ≤ N
III. K > M
Statements:
A ≤ B > E ≥ F; M > E < N
Conclusions:
I. N > F
II. B > F
Statement: I ≤ S, S < X, X = F, F ≤ K
Conclusion: I. K > I II. I < X
Statements: J > A > G < N < K = V
Conclusion
I. J > K
II. V > A
...Statements : E > N > W ≤ M > L; K ≥ G; L > P = Q > G
Conclusions :
I . M > G
II . W < N
III . L < K
...If “M % N # O © P @ S © T $ W” is true then which of the following is definitely not true?
(i) M # P
(ii) O © T
(iii) N #...
Statements: D = E ≥ G = K, O > B ≤ C = K, E ≤ I < F
Conclusions: I.F > K II. I ≥ G
...