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    Question

    The length of a rectangle is 64 cm. If the ratio of

    length to perimeter of the rectangle is 4:15, find the area of a circle whose diameter is 6 cm less than double the breadth of the rectangle. (Take ╧А = 22/7)
    A 8,828 cm┬▓ Correct Answer Incorrect Answer
    B 10,544 cm┬▓ Correct Answer Incorrect Answer
    C 2,200 cm┬▓ Correct Answer Incorrect Answer
    D 9,500 cm┬▓ Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ; Perimeter of rectangle = 2 ├Ч (length + breadth) So, 64 : [2 ├Ч (64 + breadth)] = 4 : 15 Or, 15 ├Ч 64 = 4 ├Ч 2 ├Ч (64 + breadth) Or, 960 = 8 ├Ч (64 + breadth) Or, 64 + breadth = 120 Or, breadth = 56 cm Diameter of circle = 2 ├Ч 56 - 6 = 106 cm Radius of circle = 106 ├╖ 2 = 53 cm Area of circle = ╧А ├Ч radius┬▓ = (22/7) ├Ч 53┬▓ = (22/7) ├Ч 2809 = 8,828 cm┬▓

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